Question

calcule o valor de x em cada triangulo.

Answer 1

a)seno de 60° = cateto oposto/hipotenusa
seno de 60° =2\/¨3/x
\/¨¨3/2 = 2\/¨¨3/x
\/¨¨3 . x = 2 . 2\/¨¨3
x = 4\/¨¨3/\/¨¨3
x = 4 . \/¨3  .  \/¨3 /\/¨3  .  \/¨¨3
x = 4 . \/¨¨9 / \/¨¨9
x = 4 . 3/3
x = 12/3
x = 4
b)seno de 60° = cateto oposto/ hipotenusa
seno de 60° =x/2\/¨¨3
seno de 60° =0,86 ou \/¨3/2
\/¨¨3/2 = x / 2 \/¨¨3
2 .x = 2 \/¨3 .\/¨3
2 x = 2 \/¨9
2 x = 2 .3
x = 6/2
x =3