Question

Calcule o valor de x e y no triângulo ​

Answer 1

$\tan(60) = \frac{9}{x} \\ \sqrt{3} = \frac{9}{x} \\ \sqrt{3}x = 9$

$x = \frac{9}{ \sqrt{3} } = \frac{9 \sqrt{3} }{3} \\ x = 3 \sqrt{3}$

$\tan(40) = \frac{9}{x + y} \\ 0,83 = \frac{9}{3 \sqrt{3} + y}$

$2,49 \sqrt{3} + 0,83y = 9 \\ 0,83y = 9 - 2,49 \sqrt{3} \\ y = \frac{9 - 2,49 \sqrt{3} }{0,83}$

Admitindo √3=1,73

$y = \frac{9 - 2,49. 1,73} {0,83} \\ y = 5,65$