Calcule o valor de x e y de modo que :
![\left[\begin{array}{ccc}-3&y\\x&2\\\end{array}\right]](https://tex.z-dn.net/?f=++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%26amp%3By%5C%5Cx%26amp%3B2%5C%5C%5Cend%7Barray%7D%5Cright%5D+ "\left[\begin{array}{ccc}-3&y\\x&2\\\end{array}\right]")
. ![\left[\begin{array}{ccc}2\\-3\\\end{array}\right]](https://tex.z-dn.net/?f=++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%5C%5C-3%5C%5C%5Cend%7Barray%7D%5Cright%5D+ "\left[\begin{array}{ccc}2\\-3\\\end{array}\right]")
= ![\left[\begin{array}{ccc}1\\-5\\\end{array}\right]](https://tex.z-dn.net/?f=++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C-5%5C%5C%5Cend%7Barray%7D%5Cright%5D+ "\left[\begin{array}{ccc}1\\-5\\\end{array}\right]")
Soluções para a tarefa
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Oi Thalyra. :) y=-7/3 e x=1/2
![\left[\begin{array}{ccc}-3&y\\x&2\end{array}\right] . \left[\begin{array}{ccc}2\\-3\end{array}\right] = \left[\begin{array}{ccc}1\\-5\end{array}\right] \\ \\ \left[\begin{array}{ccc}(-3.2+y.(-3))\\(x.2+2.(-3))\end{array}\right]=\left[\begin{array}{ccc}1\\-5\end{array}\right] \\ \\ \left[\begin{array}{ccc}-6-3y\\2x-6\end{array}\right]=\left[\begin{array}{ccc}1\\-5\end{array}\right] \\ \\ -6-3y=1 \\ -3y=1+6 \\ 3y=-7 \\ y=-7/3 \\ \\ \\ 2x-6=-5 \\ 2x=-5+6 \\ 2x=1 \\ x=1/2](https://tex.z-dn.net/?f=++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%26amp%3By%5C%5Cx%26amp%3B2%5Cend%7Barray%7D%5Cright%5D+.++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%5C%5C-3%5Cend%7Barray%7D%5Cright%5D+%3D+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C-5%5Cend%7Barray%7D%5Cright%5D+%5C%5C++%5C%5C+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%28-3.2%2By.%28-3%29%29%5C%5C%28x.2%2B2.%28-3%29%29%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C-5%5Cend%7Barray%7D%5Cright%5D+%5C%5C++%5C%5C+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-6-3y%5C%5C2x-6%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C-5%5Cend%7Barray%7D%5Cright%5D+%5C%5C++%5C%5C+-6-3y%3D1+%5C%5C+-3y%3D1%2B6+%5C%5C+3y%3D-7+%5C%5C+y%3D-7%2F3+%5C%5C++%5C%5C++%5C%5C+2x-6%3D-5+%5C%5C+2x%3D-5%2B6+%5C%5C+2x%3D1+%5C%5C+x%3D1%2F2 "\left[\begin{array}{ccc}-3&y\\x&2\end{array}\right] . \left[\begin{array}{ccc}2\\-3\end{array}\right] = \left[\begin{array}{ccc}1\\-5\end{array}\right] \\ \\ \left[\begin{array}{ccc}(-3.2+y.(-3))\\(x.2+2.(-3))\end{array}\right]=\left[\begin{array}{ccc}1\\-5\end{array}\right] \\ \\ \left[\begin{array}{ccc}-6-3y\\2x-6\end{array}\right]=\left[\begin{array}{ccc}1\\-5\end{array}\right] \\ \\ -6-3y=1 \\ -3y=1+6 \\ 3y=-7 \\ y=-7/3 \\ \\ \\ 2x-6=-5 \\ 2x=-5+6 \\ 2x=1 \\ x=1/2")
thalyra20121:
Oii, muito obrigada, eu tinha feito desse jeito mas achei que tivesse errado ;)
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