Question

calcule o valor de x: 4x2+8x+3=0

Answer 1

∆ = b² - 4ac
∆ = (-8)² - 4 . 4 . 3
∆ = 64 - 48
∆ = 16


x = (-b ± √∆) / 2a
x = [-(-8) ± √16] / (2 . 4)
x = (8 ± 4) / 8

x' = (8 + 4) / 8
x' = 12 / 8
x' = 3 / 2

x'' = (8 - 4) / 8
x'' = 4 / 8
x'' = 1 / 2

S = {1/2, 3/2}