Question

Calcule o valor de P, sendo P =log3 9+5(2+log2 2)-log10

Answer 1

Calcule o valor de P, sendo P =log3 9+5(2+log2 2)-log10

P = log3 9+5(2+log2 2)-log10 

P = 2 + 5[2+1] - 1 ==> 2 + 5.3 - 1 ==> 2+15-1 ==> 16
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 log 9 = x ==> 3^x = 3^2 ==> x = 2
     3
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log 2 = x ==> 2^x = 2 ==> x = 1
     2
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log10 = x ==> 10^x = 10^1 ==> x = 1