Question

Calcule o valor de
h(x) = 4x [elevado ao quadrado] - 6x + 3 para:
a) x = -2
b) x = 0
c) x = 3

Answer 1

h(x) = 4x² - 6x + 3     x = - 2
h(-2) = 4.(-2)² - 6.(- 2) + 3
h(-2) = 4.4 + 12 + 3
h(-2) = 16 + 12 + 3
h(-2) = 31

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h(x) = 4x² - 6x + 3        x = 0
h(0) = 4.0² - 6.0 + 3
h(0) = 3

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h(x) = 4x² - 6x + 3         x = 3
h(3) = 4.3² - 6.3 + 3
h(3) = 4.9 - 18 + 3
h(x) = 36 - 18 + 3
h(3) = 21

Answer 2

Resposta:

Explicação passo-a-passo:

h(x) = 4x² - 6x + 3     x = - 2

h(-2) = 4.(-2)² - 6.(- 2) + 3

h(-2) = 4.4 + 12 + 3

h(-2) = 16 + 12 + 3

h(-2) = 31

h(x) = 4x² - 6x + 3        x = 0

h(0) = 4.0² - 6.0 + 3

h(0) = 3

h(x) = 4x² - 6x + 3         x = 3

h(3) = 4.3² - 6.3 + 3

h(3) = 4.9 - 18 + 3

h(x) = 36 - 18 + 3

h(3) = 21