Question

Calcule o valor de . A=log4 (log216)-log2(log381)+log525*log0,10.01

Answer 1

Calculando passo a passo.


Log2 16=X 
16=2^x
2^4=2^x
x=4 

Log3 81
81=3^x
3^4=3^x
x=4 

Log0,1 0,01

1/100=(1/10)^x
(1/10)²=(1/10)^x
x=2 

Log5 25 
25=5^x
5²=5^x
x=2 

Log4 4-Log2 4 + 2.2
1-2+2.2 = -1+4 = 3

Answer 2

A=log₄ (log₂ 16) - log₂ (log₃ 81) + log₅ 25  * log₀,₁ 0,01

A=log₄ (log₂ 2⁴) - log₂ (log₃ 3⁴) + log₅ 5²  * log₀,₁ 10⁻²

A=log₄  4(log₂ 2) - log₂ 4(log₃ 3) + 2log₅ 5  * (-2) log₀,₁ 10

A=log₄  4(log₂ 2) - log₂ 4(log₃ 3) - 4 * log₅ 5   log₀,₁ 10

A=log₄  4 - log₂ 4 - 4 *   log₀,₁ 10

A=log₄  4 - log₂ 2² - 4 *   log 10 /log 0,1

A=log₄  4 - 2log₂ 2 - 4 *   log 10 /(-1)log 10

A=1 - 2 - 4 *   (-1)   =1-2+4=3