Question

Calcule o valor das seguintes expressões

Answer 1

IV)

a) $(-3)^2 + 6^2 = 9+36=45$

b) $(-7)^2 -4*(3) = 49 -12 = 37$

c) $3^0 - 3^{-1} + 3^2 = 1 - \frac{1}{3} + 9 = 10 -\frac{1}{3} = \frac{29}{3}$

d) $2^{-2} + (\frac{1}{3})^2 = (\frac{1}{2})^2 + \frac{1}{9} = \frac{1}{4} + \frac{1}{9} = \frac{9}{36}+\frac{4}{36} = \frac{13}{36}$