Question

Calcule o valor das proporções:

a) 2x/12 = 4/2

b) 3x/9 = 9/3

c) 3x/7 = 6/2

d) x/2 = 8/2


Rápido pfvvv e uma prova

Answer 1

Explicação passo-a-passo:

A)

$\dfrac{2x}{12} = \dfrac{4}{2}$

$2x \times 2 = 12 \times 4$

$4x = 48$

$x = \dfrac{48}{4}$

x=>12

B)

$\dfrac{3x}{9} = \dfrac{9}{3}$

$3x \times 3 = 9 \times 9$

$9x = 81$

$x = \dfrac{81}{9}$

x=>9

C)

$\dfrac{3x}{7} = \dfrac{6}{2}$

$3x \times 2 = 7 \times 6$

$6x = 42$

$x = \dfrac{42}{6}$

x=>7

D)

$\dfrac{x}{2} = \dfrac{8}{2}$

$2x = 2 \times 8$

$2x = 16$

$x = \dfrac{16}{2}$

x=>8

Answer 2

$\large\boxed{\begin{array}{l} \sf{a) \: \dfrac{2x}{12} = \dfrac{4}{2} } \\ \\ \sf{4x = 12 \times 4} \\ \\ \sf{4x = 48} \\ \\ \sf{x = \dfrac{48}{4} } \\ \\ \boxed{ \sf{x = 12}} < < \sf{resposta}\end{array}}$

$\large\boxed{\begin{array}{l} \sf{b) \: \dfrac{3x}{9} = \dfrac{9}{3} } \\ \\ \sf{9x = 9 \times 9} \\ \\ \sf{9x = 81} \\ \\ \sf{x = \dfrac{81}{9} } \\ \\ \boxed{ \sf{x = 9}} < < \sf{resposta}\end{array}}$

$\large\boxed{\begin{array}{l} \sf{c) \: \dfrac{3x}{7} = \dfrac{6}{2} } \\ \\ \sf{6x = 6 \times 7} \\ \\ \sf{6x = 42} \\ \\ \sf{x = \dfrac{42}{6} } \\ \\ \boxed{ \sf{x = 7}} < < \sf{resposta}\end{array}}$

$\large\boxed{\begin{array}{l} \sf{d) \: \dfrac{x}{2} = \dfrac{8}{2} } \\ \\ \sf{2x = 8 \times 2} \\ \\ \sf{2x = 16} \\ \\ \sf{x = \dfrac{16}{2} } \\ \\ \boxed { \sf{x = 8}} < < \sf{resposta}\end{array}}$