Question

Calcule o valor das potências (-5/2)² (-7/9)³ (-3/5)³ . (-7/9)⁰

Answer 1

Resposta:

$(\frac{-5}{2})^{2} = \frac{25}{4} \\(\frac{-7}{9})^{3} = \frac{-343}{729}\\(\frac{-3}{5})^{3} = \frac{-27}{125}\\(\frac{-7}{9})^{0} = \frac{1}{1}$

Explicação passo-a-passo:

$(\frac{-5}{2})^{2} = \frac{(-5)^{2}}{2^{2}} = \frac{25}{4}$

$(\frac{-7}{9})^{3}=\frac{(-7)^{3}}{9^{3}} = \frac{-343}{729}$

$(\frac{-3}{5})^{3} = \frac{(-3)^{3}}{5^{3}} = \frac{-27}{125}$

$(\frac{-7}{9})^{0} = \frac{(-7)^{0}}{9^{0}} = \frac{1}{1} = 1$