Question

calcule o valor das expressões numéricas:
A) (0,2)³+(0,12)²-(0,3)^6
B)(3/2)²+(1/3)-¹-3-³

Answer 1

A) (0,2)³+(0,12)²-(0,3)^6

(0,2)³=(2/10)³=8/1000=0,008
(0,12)²=(12/100)²=144/10000=0,0144
(0,3)^6=(3/10)^6=729/1000000=0,000729

(0,2)³+(0,12)²-(0,3)^6=
=0,008+0,0144-0,000729
=0,021671


B) (3/2)²+(1/3)-¹-3-³

(3/2)²=9/4
(1/3)-¹=1/(1/3)=3
3-³=1/3³=1/27

(3/2)²+(1/3)-¹-3-³=
=(9/4)+3-(1/27)    m.m.c.(1 , 4 , 27)=108
=243/108+324/108-4/108
=563/108
=5,212962963
≈5,213