Matemática, perguntado por raquelquevdo, 1 ano atrás

Calcule o valor das expressãoes a)15+[6+(8÷2)]=
b)40-[3+(10-2)÷2]=
c)[30+2×(5-3)]×2-10=
d)10+[4+(7×3+1)]-3 =
e)16+[10-(18÷3+2)+5]=
f)25-[12-(3×2+1)]=
g)90-[25+(5×2-1)+3]=
h)45+[(8×5-10÷2)+(18÷6-2)]=
i)50-2×{7+8÷2-[9-3×(5-4)]}=
j)100-3×{5+8÷2[3×(7-6)]}=
k)1000-[(2.4-6)+(2+6.4)]=
l)60+2{[4.(6+2)-10]+12}=
m)[(4+16.2).5-10].100=
n){10+[5.(4+25)-8].2}-100=
o)80-5(28-6.4)+6-3.4=​

Soluções para a tarefa

Respondido por IdeiaCerta
6
A)15+[6+(8÷2)]

15+6+4

15+10

= 25

B)40-[3+(10-2)÷2]

   40 \:  \:  -  \: (3 +  \frac{8}{2})
40 − ( 3+ 4)

40 − 7

= 33

C)[30+2×(5-3)]×2-10

(30+(2)(2))(2)−10

(30+4)(2)−10

(34)(2)−10

68−10

= 58

D)10+[4+(7×3+1)]-3

10+4+21+1−3

10+4+22−3

10+26−3

36−3

= 33

E)16+[10-(18÷3+2)+5]

16+10−(6+2)+5

16+10−8+5

16+2+5

16+7

= 23

F)25-[12-(3×2+1)]

25−(12−(6+1))

25−(12−7)

25−5

= 20

G)90-[25+(5×2-1)+3]


90−(25+10−1+3)

90−(25+9+3)

90−(34+3)

90−37

= 53

H)45+[(8×5-10÷2)+(18÷6-2)]

45 + 40 - 10/2 + 18/6 - 2

45 + 40 - 5 + 18/6 - 2

45 + 35 + 18/6 -2

45 + 35 + 3 - 2

45 + 35 - 1

45 + 36

= 81

I)50-2×{7+8÷2-[9-3×(5-4)]}

50−2(7+4−(9−3(5−4)))

50−2(11−(9−3(5−4)))

50−2(11−(9−(3)(1)))

50−2(11−(9−3))

50−2(11−6)

50−(2)(5)

50−10


= 40

J)100-3×{5+8÷2[3×(7-6)]}

100−3(5+4(3(7−6)))

100−3(5+4(3)(1))

100−3(5+(4)(3))

100−3(5+12)

100−(3)(17)

100−51


= 49

K)1000-[(2×4-6)+(2+6×4)]

1000−(8−6+2+(6)(4))

1000−(2+2+(6)(4))

1000−(2+2+24)

1000−(2+26)

1000−28

= 972

L)60+2{[4×(6+2)-10]+12}

60+2((4)(8)−10+12)

60+2(32−10+12)

60+2(22+12)

60+(2)(34)

60+68

= 128


M)[(4+16×2)×5-10]×100

((4+32)(5)−10)(100)

((36)(5)−10)(100)

(180−10)(100)

(170)(100)

= 17000

N){10+[5×(4+25)-8]×2}-100

10+((5)(29)−8)(2)−100

10+(145−8)(2)−100

10+(137)(2)−100

10+274−100

284−100


= 184

O)80-5(28-6×4)+6-3×4

80−5(28−24)+6−(3)(4)

80−(5)(4)+6−(3)(4)

80−20+6−(3)(4)

60+6−(3)(4)

66−(3)(4)

66−12


= 54






















raquelquevdo: obrigada❤
Respondido por Usuário anônimo
3

Resposta:

Calcule o valor das expressões:

a)

= 15+[6+(8÷2)]

= 15 +[6+4]

= 15+10

= 25

b)

= 40-[3+(10-2)÷2]

= 40 - [3 + 8 : 2]

= 40 - [ 3 + 4]

= 40 - 7

= 33

c)[30+2×(5-3)]×2-10

= [30 + 2.2]. 2- 10

= [30 + 4]. 2 - 10

= 34.2 - 10

= 68 - 10

= 58

d)

= 10+[4+(7×3+1)]-3

= 10 + [4 + (21+1)] - 3

= 10 + [4+22] - 3

= 10 + 26 - 3

= 36 - 3

= 33

e)

= 16+[10-(18÷3+2)+5]

= 16 + [10 - (6+2) + 5]

= 16 + [10 - 8 +5]

= 16 + 7

= 23

f)

= 25-[12-(3×2+1)]

= 25 - [ 12 - (6+1)]

= 25 - [12 - 7]

= 25 - [5]

= 20

g)

= 90-[25+(5×2-1)+3]

= 90 - [ 25+(10-1)+3]

= 90 - [ 25+9+3]

= 90 - 37

= 53

h)

= 45+[(8×5-10÷2)+(18÷6-2)]

= 45+[(40-5)+(3-2)]

= 45+[35+1]

= 45+36

= 81

i)

=50-2×{7+8÷2-[9-3×(5-4)]}

=50- 2.{7+4-[9 - 3.1]}

=50 - 2.{ 7+4 - [9-3]}

=50 - 2.{11 - 6}

= 50 - 2.5

= 50 - 10

= 40

j)

= 100-3×{5+8÷2[3×(7-6)]}

= 100 - 3.{5+4.[3.1]}

= 100 - 3.{5 + 4. 3}

= 100 - 3.{5 + 12}

= 100 - 3.17

= 100 - 51

=49

k)

= 1000-[(2.4-6)+(2+6.4)]

= 1000 - [(8-6)+( 2+24)]

= 1000 - [ 2+ 26]

= 1000 - 28

= 972

l)

= 60+2{[4.(6+2)-10]+12}

= 60 + 2.{[4.8 - 10] + 12}

= 60 + 2.{[32 - 10] + 12}

= 60 + 2.{22 + 12}

= 60 + 2.34

= 60 + 68

= 128

m)

= [(4+16.2).5-10].100

= [(4+32).5 - 10]. 100

= [36.5- 10]. 100

= [180 - 10]. 100

= 170.100

= 17000

n)

= {10 + [5.(4+25)-8].2}-100

={10 +[5.29 - 8]. 2} - 100

= { 10 + [145 - 8]. 2} - 100

={ 10 + 137.2} - 100

={ 10 + 274}- 100

= 284 - 100

= 184

o)

= 80-5(28-6.4)+6-3.4

= 80 - 5.(28-24)+6-12

= 80 - 5.4 - 6

= 80 - 20 - 6

= 60 - 6

= 54

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