Question

Calcule o valor da Integral

Answer 1

Resposta:

1 a 2∫  0 a 3 ∫ 1 a 2 ∫ (x²z) dx dy dz

1 a 2∫  0 a 3 ∫ 1 a 2 [ zx³/3] dy dz

1 a 2∫  0 a 3 ∫    z*[8/3 -1/3] dy dz

1 a 2∫  0 a 3 ∫    z*[7/3] dy dz

1 a 2∫  0 a 3 [z*[7/3] * y ] dz

1 a 2∫  z*[7/3] * 3  dz

1 a 2∫  7z  dz

1 a 2 [ 7z²/2 ] =(7/2) * (2²-1)  =21/2 unid. volume