Matemática, perguntado por lucagimenes16, 5 meses atrás

Calcule o valor da incógnita.
a) 9 ( x + 2 ) < 19

b) 5x + 10 > 15

c) 2x – 4 > 3 ( x – 8 ) d) x + 3 < 12 – 2x

Soluções para a tarefa

Respondido por LucasPereiraBrito
1

Resposta:

Explicação passo a passo:

A

9 ( x + 2) < 19

9x + 18 < 19

9x < 19 - 18

9x < 1

x < 1/9

B

5x + 10 > 15

5x > 15 - 10

5x > 5

x > 1

C

2x – 4 > 3 ( x – 8 )

2x - 4 > 3x - 24

2x - 3x > - 24 + 4

- x > - 20 (-1)

x < 20

D

x + 3 < 12 – 2x

x + 2x < 12 - 3

3x < 9

x < 9/3

x < 3

Respondido por Usuário anônimo
2

Resposta:

a)x&lt;\frac{1}{9} \\\\b)x&gt;1\\\\c)x&lt;20\\\\d)x&lt;3

Explicação:

a)9(x+2)&lt;19\\\\\frac{9(x+2)}{9} &lt;\frac{19}{9} \\\\x+2&lt;\frac{19}{9} \\\\x+2-2&lt;\frac{19}{9}-2\\\\x&lt;\frac{1}{9} \\\\\\b)5x+10&gt;15\\\\5x+10-10&gt;0\\\\5x&gt;15-10\\\\5x&gt;5\\\\x&gt;5:5\\\\x&gt;1\\\\\\c)2x-4&gt;3(x-8)\\\\2x-4&gt;3x-24\\\\2x-4+4=0\\\\2x&gt;3x-24+4\\\\2x&gt;3x-20\\\\2x-3x&gt;20-3x\\\\-x&gt;-20\\\\(-x)(-1)&lt;(-20)(-1)\\\\x&lt;20\\

d)x+3&lt;12-2x\\\\x+3-3=0\\\\x&lt;12-2x-3\\\\x&lt;-2x+9\\\\x+2x&lt;9+2x\\\\x&lt;9:3\\\\x&lt;3

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