Question

Calcule o valor da hipotenusa e do cateto.

Answer 1

Explicação passo-a-passo:

• Cateto

$\sf tg~60^{\circ}=\dfrac{cateto~oposto}{cateto~adjacente}$

$\sf \sqrt{3}=\dfrac{12\sqrt{3}}{b}$

$\sf b\sqrt{3}=12\sqrt{3}$

$\sf b=\dfrac{12\sqrt{3}}{\sqrt{3}}$

$\sf b=12$

• Hipotenusa

$\sf sen~60^{\circ}=\dfrac{cateto~oposto}{hipotenusa}$

$\sf \dfrac{\sqrt{3}}{2}=\dfrac{12\sqrt{3}}{a}$

$\sf a\sqrt{3}=12\sqrt{3}\cdot2$

$\sf a\sqrt{3}=24\sqrt{3}$

$\sf a=\dfrac{24\sqrt{3}}{\sqrt{3}}$

$\sf a=24$