Question

Calcule o valor da expressão (FOTO ABAIXO)
me ajudem

Answer 1

Vamos la:

Sen 120° = Sen 60°
Sen 240° = Sen 60°
Sen 330° = Sen 30°
Sen 180° = 0

Substituindo:

A = V3.(Sen 60° - Sen 60°)/Sen 30°
A = 0/Sen 30°
A = 0

espero ter ajudado

Answer 2

$\text{sen}\,120^\circ=\dfrac{\sqrt3}{2}\qquad\text{sen}\,240^\circ=-\dfrac{\sqrt3}{2}\qquad\text{sen}\,330^\circ=-\dfrac{1}{2}\qquad\text{sen}\,180^{\circ}=0\\\\\\\\A=\dfrac{\sqrt3(\text{sen}\,120^\circ-\text{sen}\,240^\circ)}{\text{sen}\,330^\circ-\text{sen}\,180^\circ}\\\\\\A=\dfrac{\sqrt3\left(\dfrac{\sqrt3}{2}-\!\!\left(\!\!-\dfrac{\sqrt3}{2}\right)\right)}{-\dfrac{1}{2}-0}\\\\\\A=\dfrac{\sqrt3\left(\dfrac{\sqrt3}{2}+\dfrac{\sqrt3}{2}\right)}{-\dfrac{1}{2}}\\\\\\A=\dfrac{\sqrt3(\sqrt3)}{-\dfrac{1}{2}}\\\\\\A=\dfrac{3}{-\dfrac{1}{2}}\\\\\\A=3\cdot{-\dfrac{2}{1}}\\\\\\A=3\cdot-2\\\\\boxed{A=-6}$