Question

Calcule o valor da expressão abaixo, sabendo que senx = 3/5.

Cos x+ tag x.

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Answer 1

$\mathsf{sen^2(x)=(\dfrac{3}{5})^2=\dfrac{9}{25}}$

$\mathsf{cos^2(x)=\dfrac{16}{25}\to~cos(x)=\dfrac{4}{5}}$

$\mathsf{tg(x)=\dfrac{sen(x)}{cos(x)}}\\\mathsf{tg(x)=\dfrac{\frac{3}{5}}{\frac{4}{5}}=\dfrac{3}{4}}$

$\mathsf{cos(x)+tg(x)=\dfrac{4}{5}+\dfrac{3}{4}=\dfrac{16+15}{20}=\dfrac{31}{20}}$