Question

calcule o valor da equação de 2o grau : 9x²-24x+16=0

Answer 1

$9x^2 - 24x + 16 = 0$


Δ = b²−4ac
Δ = (−24)²−4⋅9⋅16
Δ = 576−576
Δ = 0


$x = \dfrac{-b \pm \sqrt{\Delta}}{2*a}\\ \\ \\ x = \dfrac{-(-24) \pm \sqrt{0}}{2*9}\\ \\ \\x = \dfrac{24 \pm 0}{18}\\ \\ \\x' = \dfrac{24 + 0}{18}\\ \\ \\x' = \dfrac{24}{18}\\ \\ \\x' = \dfrac{4}{3}\\ \\ \\x'' = \dfrac{24 - 0}{18}\\ \\ \\x'' = \dfrac{4}{3}$


$S = \{ \dfrac{4}{3} ~\}$