Question

Calcule o sen B, cos B e tg B no triângulo.

Answer 1

$2 \sqrt{10}$
5÷□×20=
20×□=
20÷5=5
□=A+B
□=3

Answer 2

Olá,

*Seno = $\frac{cateto oposto}{hipotenusa}$

*Cosseno = $\frac{cateto adjacente}{hipotenusa}$

*Tangente = $\frac{cateto oposto}{cateto adjacente}$

Dessa maneira temos:

sen B = $\frac{2}{2\sqrt{10}}$ = $\frac{\sqrt{10}}{10}$

cos B = $\frac{6}{2\sqrt{10}}$ = $\frac{3\sqrt{10}}{10}$

tg B =  $\frac{2}{6}$ = tex]\frac{1}{3}[/tex]