Calcule o resultado de cada divisao e simplifique quanto possível.
A)28÷ 7/3
B)3/10÷18/100
C)36/5÷8/15
D)1÷3/4
E)76/125÷8/5
F) 100/101÷100
G)10÷40/13
Soluções para a tarefa
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A regra é: A fração que está dividindo no denominado passa a multiplicar invertido. Observa o negrito:
a) 28÷7/3 = 28 x 3/7 = 84/7 = 12
b) (3/10) ÷ (18/100) = (3/10)x(100/18) = (3 x 100)/(10 x 18) = 300/180 = 30/18 = 5/3
c) (36/5)÷(8/15) = (36/5)x(15/8) = (36x15)x(5x8) = 540/40 = 54/4 = 27/2
d) 1÷(3/4) = (1/1)x(4/3) = (1x4)c(1x3) = 4/3
e) (76/125)÷(8/5) = (76/125)x(5/8) = (76x5)/(125x8) = 380/1000 = 38/100 = 16/50 = 8/25
f) (100/101)÷(100/1) = (100/101)/(1/100) = (100x1)/(101x100)= 1/101
g) 10÷(40/13) = (10/1)÷(13/40) = (10x13)/(1x40) = 130/40 = 13/4
a) 28÷7/3 = 28 x 3/7 = 84/7 = 12
b) (3/10) ÷ (18/100) = (3/10)x(100/18) = (3 x 100)/(10 x 18) = 300/180 = 30/18 = 5/3
c) (36/5)÷(8/15) = (36/5)x(15/8) = (36x15)x(5x8) = 540/40 = 54/4 = 27/2
d) 1÷(3/4) = (1/1)x(4/3) = (1x4)c(1x3) = 4/3
e) (76/125)÷(8/5) = (76/125)x(5/8) = (76x5)/(125x8) = 380/1000 = 38/100 = 16/50 = 8/25
f) (100/101)÷(100/1) = (100/101)/(1/100) = (100x1)/(101x100)= 1/101
g) 10÷(40/13) = (10/1)÷(13/40) = (10x13)/(1x40) = 130/40 = 13/4
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