Question

Calcule o pH ou pOH.

A) [H+] = 10^-7 mol/L

B) [OH-] = 10^-14 mol/L

C) [H+] = 10^0 mol/L

D) [H+] = 5 × 10^-4 mol/L

E) [OH-] = 3,0 × 10^1


Me ajudem!!!

Answer 1

a) ph= - log [H+]
pH = - log (10^-7)
pH =7

b) pOH = - log [OH]
pOH =-log ( 10^-14)
pOH = 14

c) pH= - log 10^0
ph= 0

d) pH = - log ( 5x10^-4)
pH = 3,30

e) pOH = - log (3,0x10^1)
pOH = 0,52