Question

calcule o perimitro do triangulo a(1,1) b (2,3) c(5,-1)

Answer 1

$AB= \sqrt{(2-1)^2+(3-1)^2}=\sqrt{1^2+2^2}=\sqrt{5}$

$AC= \sqrt{(5-1)^2+(-1-1)^2}=\sqrt{16+4}=\sqrt{20}=2\sqrt{5}$

$BC= \sqrt{(5-2)^2+(-1-3)^2}=\sqrt{9+16}=\sqrt{25}=5$

$Perimetro=\sqrt{5}+2\sqrt{5}+5=3\sqrt{5}+5$


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