Question

calcule o perímetro do triângulo de vértices A (1,1) B(5, -2) e C (5,4).

Answer 1

usa a formula$\sqrt{}$(x1-x2)²+(y1-y2)²=
ab=$\sqrt{}$(1-5)²+(1-(-2))²=$\sqrt{}$(4)²+(3)²=$\sqrt{}$16+9=5
ac=$\sqrt{}$(1-5)²+(1-4)²=$\sqrt{}$(4)²+(3)²=$\sqrt{}$16+9=5
bc= $\sqrt{}$(5-5)²+(-2-4)²=$\sqrt{}$0+36=6
perimetro=soma dos vertices=5+5+6=16