calcule o perímetro de cada triângulo
obg <3
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x^2=6^2+8^2
x^2= 36 + 64
x^2= 100
x=10
8+6+10= 24m
14,4^2=6^+x^2
207,36=36+x^2
171,36=x^2
x= 13,09
13,09+6+14,4= 33.49m
11,6^2= 8,4^2+x^2
134,56= 70,56 + x^2
134,56-70,56=x^2
64=x^2
x= 8m
8+11,6+8,4
28m
x^2= 15^2+9^2
x^2= 225 + 81
x^2=306
x= 17,49
17,4+15+9= 41,4
x^2= 36 + 64
x^2= 100
x=10
8+6+10= 24m
14,4^2=6^+x^2
207,36=36+x^2
171,36=x^2
x= 13,09
13,09+6+14,4= 33.49m
11,6^2= 8,4^2+x^2
134,56= 70,56 + x^2
134,56-70,56=x^2
64=x^2
x= 8m
8+11,6+8,4
28m
x^2= 15^2+9^2
x^2= 225 + 81
x^2=306
x= 17,49
17,4+15+9= 41,4
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