Question

calcule o oitavo termo da P.G de razão 2 e primeiro termo igual a 6

Answer 1

$> \: resolucao \\ \\ \geqslant \: progressao \: \: geometrica \\ \\ a1 = 6 \\ q = 2 \\ n = 8 \\ \\ = = = = = = = = = = = = = = = = = \\ \\ > \: o \: oitavo \: termo \: da \: pg \\ \\ an = a1 \times q {}^{n - 1} \\ an = 6 \times 2 {}^{8 - 1} \\ an = 6 \times 2 {}^{7} \\ an = 6 \times 128 \\ an = 768 \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \geqslant$

Answer 2

$\mathsf{ a_n=a_1*q^{n-1}}$

$\mathsf{a_8=6*2^{8-1} }$

$\mathsf{a_8=6*2^7 }$

$\boxed{\boxed{\mathsf{a_8=768 }}}$