Question

calcule o numero de mols presentes em :20g de KBR80 g de NAOH15G DE NACL

Answer 1

Massa molar:
KBr - 119g
NaOH - 40g
NaCl - 58,5g


1 mol --- 119g de KBr
x mols --- 20
119 x = 20
x = 20/119
x = 0,168 mols de KBr

1 mol --- 40g NaOH
x mols -- 80g
40x = 80
x = 80/40
x = 2 mols NaOH

1 mol -- 58,5g NaCl
x mols -- 15g
58,5gx -- 15g
x = 15/58,5
x = 0,2564mols NaCl