Matemática, perguntado por rutzluan794, 6 meses atrás

calcule o mmc dos seguintes numeros(processo pratico)
a) 15 e 45
b)50 e 100
c)2 e 6
d) 10 e 20​

Soluções para a tarefa

Respondido por CyberKirito
2

\Large\boxed{\begin{array}{l}\tt a)\\\begin{array}{c|c}\sf15,45&\sf3\\\sf5,15&\sf3\\\sf5,5&\sf5\\\sf1,1\end{array}\\\sf m\cdot m\cdot c~(15,45)=3\cdot3\cdot5=45\end{array}}

\Large\boxed{\begin{array}{l}\tt b)\\\begin{array}{c|c}\sf50,100&\sf2\\\sf25,50&\sf2\\\sf25,25&\sf5\\\sf5,5&\sf5\\\sf1,1\end{array}\\\sf m\cdot m\cdot c~(50,100)=2\cdot2\cdot5\cdot5=100\end{array}}

\Large\boxed{\begin{array}{l}\tt c)\\\begin{array}{c|c}\sf2,6&\sf2\\\sf1,3&\sf3\\\sf1,1\end{array}\\\sf m\cdot m\cdot c~(2,6)=2\cdot3=6\end{array}}

\Large\boxed{\begin{array}{l}\tt d)\\\begin{array}{c|c}\sf10,20&\sf2\\\sf5,10&\sf2\\\sf5,5&\sf5\\\sf1,1\end{array}\\\sf m\cdot m\cdot c~(10,20)=2\cdot2\cdot5=20\end{array}}

Respondido por Trash66x
0

a) 15 - 45 / 3

5 - 15 / 3

5 - 5 / 5

1 - 1 /

mmc = 3² × 5 = 45

b)50 - 100 / 2

25 - 50 / 2

25 - 25 / 5

5 - 5 / 5

1 - 1 /

mmc = 2²× 5² = 100

c)2 - 6 / 2

1 - 3 / 3

1 - 1 /

mmc = 2 × 3 = 6

d) 10 - 20 / 2

5 - 10 / 2

5 - 5 / 5

1 - 1 /

mmc = 2² × 5 = 20

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