Question

Calcule o logaritmo.

Log258 128

Answer 1

Explicação passo-a-passo:

$\sf log_{256}~128=x$

$\sf 256^x=128$

$\sf (2^8)^x=2^7$

$\sf 2^{8x}=2^7$

Igualando os expoentes:

$\sf 8x=7$

$\sf \red{x=\dfrac{7}{8}}$

Answer 2

Oie, Td Bom?!

$= log_{256}(128)$

$= log_{2 {}^{8} }(2 {}^{7} )$

$= \frac{7}{8} \: . \: log_{2}(2)$

$= \frac{7}{8} \: . \: 1$

$= \frac{7}{8}$

$= 0,875$

Att. Makaveli1996