Question

Calcule o logaritmo 256 na base 2 raiz de 32

Answer 1

(2V32)^x = 256

(V(2^2 . 2^5) )^x = 2^8

((2^7)^1/2)^x = 2^8

(2^7/2)^x = 2^8

2^7x/2 = 2^8

7x/2 = 8

7x = 16

x = 16/7