calcule o log 0,001 base 10 + log de 3 raiz de 3 na base 3 - log 1 base 81
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Natália,
Vamos passo a passo
Aplicando propriedades operatórias de logaritmos
![log0,001 + log(3)3 \sqrt{3} -log(81)1 \\ \\ =log10 ^{-3} +[log(3)3+log(3) 3^{ \frac{1}{2} }] -log(81)1 \\ \\ =-3log10+[[log(3)3+ \frac{1}{2}log(3)3]-log(81)1 \\ \\ =-3x1+[1+ \frac{1}{2} x1]-0 \\ \\ =-3+1+ \frac{1}{2} +0 \\ \\= -3+ \frac{3}{2} \\ \\ =- \frac{6}{2} + \frac{3}{2}](https://tex.z-dn.net/?f=log0%2C001+%2B+log%283%293+%5Csqrt%7B3%7D+-log%2881%291+%5C%5C++%5C%5C+%3Dlog10+%5E%7B-3%7D+%2B%5Blog%283%293%2Blog%283%29+3%5E%7B+%5Cfrac%7B1%7D%7B2%7D+%7D%5D+-log%2881%291+%5C%5C++%5C%5C+%3D-3log10%2B%5B%5Blog%283%293%2B+%5Cfrac%7B1%7D%7B2%7Dlog%283%293%5D-log%2881%291++%5C%5C++%5C%5C+%3D-3x1%2B%5B1%2B+%5Cfrac%7B1%7D%7B2%7D+x1%5D-0+%5C%5C++%5C%5C+%3D-3%2B1%2B+%5Cfrac%7B1%7D%7B2%7D+%2B0+%5C%5C++%5C%5C%3D+-3%2B+%5Cfrac%7B3%7D%7B2%7D+%5C%5C++%5C%5C+%3D-+%5Cfrac%7B6%7D%7B2%7D++%2B+%5Cfrac%7B3%7D%7B2%7D+ "log0,001 + log(3)3 \sqrt{3} -log(81)1 \\ \\ =log10 ^{-3} +[log(3)3+log(3) 3^{ \frac{1}{2} }] -log(81)1 \\ \\ =-3log10+[[log(3)3+ \frac{1}{2}log(3)3]-log(81)1 \\ \\ =-3x1+[1+ \frac{1}{2} x1]-0 \\ \\ =-3+1+ \frac{1}{2} +0 \\ \\= -3+ \frac{3}{2} \\ \\ =- \frac{6}{2} + \frac{3}{2}")
RESULTADO FINAL
Vamos passo a passo
Aplicando propriedades operatórias de logaritmos
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