Question

calcule o determinante da ordem 3:
4 0 3
-1 2 4
2 1 1​

Answer 1

$\left[\begin{array}{ccc}4&0&3\\-1&2&4\\2&1&1\end{array}\right]$$\left[\begin{array}{ccc}4&0\\-1&2\\2&1\end{array}\right]$

(4x2x1)+(0x4x2)+(3x-1x1)-(2x2x3)-(1x4x4)-(1x-1x0)=8-3-12-16= -23