Question

calcule o coeficiente angular que passa pelos pontos A(4,2 ) é B ( 6,8 )​

Answer 1

O coeficiente angular da reta é igual a 3.

Para calcular o coeficiente angular da reta, aplica-se a fórmula

$m = (yb - ya) / (xb - xa)\\\\m = (8 - 2) / (6 - 4)\\\\m = 6 / 2\\\\m = 3$

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Answer 2

✅ Tendo resolvido os cálculos, concluímos que o coeficiente angular procurado é:

  $\Large\displaystyle\text{ \begin{gathered}\boxed{\boxed{\:\:\:\bf m = 3\:\:\:}}\end{gathered} }$

 

Sejam os pontos:

      $\Large\begin{cases} A(4, 2)\\B(6, 8)\end{cases}$

Para calcular o coeficiente angular "m" devemos utilizar a seguinte estratégia:

      $\Large\displaystyle\begin{gathered} m = \tan \theta\end{gathered}$

            $\Large\displaystyle\begin{gathered} = \frac{\sin \theta}{\cos \theta}\end{gathered}$

            $\Large\displaystyle\text{ \begin{gathered} = \frac{y_{B} - y_{A}}{x_{B} - x_{A}}\end{gathered} }$

            $\Large\displaystyle\begin{gathered} = \frac{8 - 2}{6 - 4}\end{gathered}$

            $\Large\displaystyle\begin{gathered} = \frac{6}{2}\end{gathered}$

            $\Large\displaystyle\begin{gathered} = 3\end{gathered}$

✅ Portanto, o coeficiente angular é:

        $\Large\displaystyle\begin{gathered} m = 3\end{gathered}$

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