Question

calcule o coeficiente angular da reta que contem os pontos A (1,7) e B (5,1)​

Answer 1

Resposta:

$A(1,7)\\y=mx+n\\7=m+n\\\\B(5,1)\\y=mx+n\\1=5m+n\\\\\left \{ {{m+n=7} \atop {5m+n=1}} \right. \\\left \{ {{m+n=7*(-1)} \atop {5m+n=1}} \right. \\\left \{ {{-m-n=-7} \atop {5m+n=1}} \right. \\5m-m+n-n=1-7\\4m=-6\\m=(\frac{-6:2}{4:2})\\\\m=-\frac{3}{2}$

O coeficiente angular é  $-\frac{3}{2}$  .

Explicação passo-a-passo: