Question

calcule o 10° termo da pg (1,-2,4,-8)

Answer 1

$q = \frac{a2}{a1} = \frac{ - 2}{1} = - 1 \\ a10 = a1. {q}^{9} \\ a10 = 1 \times {( - 1)}^{9} \\ a10 = 1 \times ( - 1) \\ a10 = - 1$