Question

Calcule MM:
O=16 N=14 H=1 P=31 C=12
a) CO2
b) NH3
c) HNO3
d) C20 H33 O11

Answer 1

a) CO2

12 + (2 x 16) =  44g/mol

b) NH3

14 + (3 x 1) = 17g/mol

c) HNO3

1 + 14 + (3 x 16) = 63g/mol

d) C20H33O11

(20 x 12) + (33 x 1) + (11 x 16) = 240 + 33 + 176 = 449g/mol