Question

Calcule, me ajudem da E) pra frente, coloquem as contas pfv!!!!​

Answer 1

e)

$\sqrt{4}-\sqrt{1}=\sqrt{2^2}-\sqrt{1^2}=2-1=\boxed{1}$

f)

$\sqrt{25}-\sqrt[3]{8}=\sqrt{5^2}-\sqrt[3]{2^3}=5-2=\boxed{3}$

g)

$\sqrt[3]{27}+\sqrt[4]{16}=\sqrt[3]{3^3}+\sqrt[4]{2^4}=3+2=\boxed{5}$

h)

$\sqrt[3]{125}-\sqrt[3]{8}=\sqrt[3]{5^3}-\sqrt[3]{2^3}=5-2=\boxed{3}$

i)

$\sqrt{25}-\sqrt{4}+\sqrt{16}=\sqrt{5^2}-\sqrt{2^2}+\sqrt{4^2}=5-2+4=\boxed{7}$

j)

$\sqrt{49}+\sqrt{25}-\sqrt[3]{64}=\sqrt{7^2}+\sqrt{5^2}-\sqrt[3]{4^3}=7+5-4=\boxed{8}$