Question

calcule: log3 2 + log3 (x+1) = 1

Answer 1

Lembre-se:

$log_{b} x + log_{b} y <=> log_{b} (x*y)$
$log_{b}a = c <=> b^{c} = a$
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$log_{3}2 + log_{3}(x+1) = 1$
$log_{3} [2*(x + 1)] = 1$
$log_{3} (2x + 2) = 1$
$3^{1} = 2x + 2$
$3 - 2 = 2x$
$2x = 1$
$x = 1/2$