Question

calcule : log 1/2 32=X

Answer 1

log1/2 32= x

32 = 2^5
1/2 = 2^(-1)

Substiuímos 1/2 por 2^(-1) e 32 por 2^5:
log1/2 32 = x
log2^(-1) 2^5 = x
2^(-1x) =2^5
-x = 5
x = - 5