Question

Calcule limites a seguir :

Answer 1

A)

$\displaystyle \lim_{x \to 6^+} \frac{4}{x-6} = \frac{4}{0^+}=+\infty$

B)

$\displaystyle \lim_{x \to 6^-} \frac{4}{x-6} = \frac{4}{0^-}=-\infty$

C)

$\displaystyle \lim_{x \to 1^+} \frac{3}{1-x} = \frac{3}{0^-}=-\infty$

D)

$\displaystyle \lim_{x \to 1^-} \frac{3}{1-x} = \frac{3}{0^+}=+\infty$

E)

$\displaystyle \lim_{x \to 0^+} \frac{x+5}{x} = \frac{5}{0^+}=+\infty$

F)

$\displaystyle \lim_{x \to 0^-} \frac{x+5}{x} = \frac{5}{0^-}=-\infty$

G)

$\displaystyle \lim_{x \to 1^+} \frac{x^2}{x-1} = \frac{1}{0^+}=+\infty$

H)

$\displaystyle \lim_{x \to 1^-} \frac{x^2}{x-1} = \frac{1}{0^-}=-\infty$

I)

$\displaystyle \lim_{x \to 0^+} \frac{-1}{x^2} = \frac{-1}{0^+}=-\infty$

J)

$\displaystyle \lim_{x \to 0^-} \frac{-1}{x^2} = \frac{-1}{0^+}=-\infty$