Question

Calcule, indicando o resultado sem radical.

Answer 1

$\sqrt{3} * \sqrt{12} = \sqrt{36} = 6 \sqrt[3]{2} * \sqrt[3]{4} = \sqrt[3]{8} = 2 c) \sqrt[5]{8} * \sqrt[5]{4} = \sqrt[5]{ 2^{5} } = 2 d) \sqrt{11} * \sqrt{11} = \sqrt{11^{2}} = 11 e) \sqrt{2} * \sqrt{50} = \sqrt{100} = 10 f) \sqrt{8} * \sqrt{1/2} = \sqrt{8*2^{-1}} = \sqrt{2^{3} * 2^{-1}}} = 2 g) \sqrt{ \frac{1}{10} } * \sqrt{10} = \sqrt{ \frac{10}{10} } = 1 h) \sqrt{ \frac{1}{2} } * \sqrt{5} * \sqrt{10} = \sqrt{ \frac{5*10}{2} } = \sqrt{25} = 5$