Question

calcule f(π/2) para f(x)= sen2x-4 cos x+ sen x /3+cos 2x

Answer 1

Temos um função do tipo;

f(x) = sen 2x - 4cos x + sen x/3 + cos 2x

π = 180° → π/2 = 90° valor de x

f(π/2) = sen 2(π/2) - 4cos (π/2) + sen (π/2)/3 + cos 2(π/2)

f(π/2) = Sen π - 4cos (π/2) + sen (π/2)/3 + cos π

Como;

sen π = 0 , cos π/2 = 0 e sen π/2 = 1 , cos π = -1 Temos;

f(π/2) = 0 - 4.0 + 1/3 - 1

f(π/2) = 1/2