Question

calcule f(1/2),f(-3),f(0),f(-4)da funçao f(x)=3x^2-2x+6

Answer 1

Resposta:

f(1/2) = 3(1/2)² - 2 (1/2) + 6

f(1/2) = 3/4 -2/2 + 6

f(1/2) = 3/4 -1 + 6

f(1/2) = 3/4 + 5

f(1/2) = 23/4

f(-3) = 3(-3)² - 2(-3) + 6

f(-3) = 3 * 9 -(-6) + 6

f(-3) = 27 + 6 + 6

f(-3) = 27 + 12

f(-3) = 39

f(0) = 3 * 0² - 2 * 0 + 6

f(0) = 0 - 0 + 6

f(0) = 6

f(-4) = 3(-4)² - 2(-4) + 6

f(-4) = 3 * 16 -(-8) + 6

f(-4) = 48 + 8 + 6

f(-4) = 62