Question

calcule esse numero
$x^{2} +x=12$

Answer 1

x²+x=12
x²+x-12=0            a)1   b)1 c)-12
Δ= b²-4.a.c
Δ= 1²-4.1.-12
Δ= 1+48
Δ=49
 -b+/-√Δ /2.a
-1+/-√49 /2.1
 -1+/-7 /2
x'= -1+7 /2= 6/2= 3
x''= -1-7/2= -8/2= -4
{3,-4}