Question

calcule esse limite:
x²+2x-3
_______
5-3x
x tende a -3

Answer 1

$\lim_{x \to -3} \frac{x^2+2x-3}{5-3x}=\frac{(-3)^2+2(-3)-3}{5-3(-3)}=\frac{9-6-3}{5+9}=\frac{0}{14}=\boxed{0}$