Question

Calcule essa combinação A13,3 e C13,3

Answer 1

Resposta:

$A_n,_p=\frac{n!}{(n-p)!} \\\\A_1_3,_3=\frac{13!}{(13-3)!} =\frac{13!}{10!}=\frac{13.12.11.10!}{10!}=13.12.11=1716$

$C_n,_p=\frac{n!}{p!(n-p)!} =\frac{13!}{3!(13-3)!} =\frac{13.12.11.10!}{3.2.1.10!} =\frac{1716}{6}=286$