Question

Calcule e simplifique o resiltado quando for possivel
A)5/8 +7/12=
B)7/9- 1/6=
c)4/5 + 1/2 -5/8 =
d)7/15 + 3/15 -1/10 =​

Answer 1

Resposta:

Explicação passo-a-passo:

A) $\frac{5}{8}$ +$\frac{7}{12\\}$= $\frac{29}{24}$

MMC de 8 e 12= 24

8, 12   I  2

4, 6    I  2

2, 3    I  2

1,  3    I  3

1,1       I 2 · 2 · 2 · 3 = 24

$\frac{24/8*5}{24}$ + $\frac{24/12*7}{24}$ =

$\frac{3*5}{24}$ +  $\frac{2*7}{24}$ =

$\frac{15}{24}$ + $\frac{14}{24}$ = $\frac{29}{24}$

B) $\frac{7}{9} - \frac{1}{6}$ = $\frac{11}{18\\}$

MMC de 9 e 6

9, 6  I  2

9, 3  I  3

3, 1   I  3

1, 1    I 2 * 3 * 3 = 18

$\frac{18/9*7}{18} - \frac{18/6*1}{18}$ =

$\frac{2*7}{18} - \frac{3*1}{18}$ =

$\frac{14}{18}- \frac{3}{18} = \frac{11}{18\\}$

C) $\frac{4}{5} + \frac{1}{2} - \frac{5}{8} =$ $\frac{27}{40\\}$

MMC de 5, 2 e 8:

5, 2, 8  I  2

5, 1, 4   I  2

5, 1, 2   I  2

5, 1, 1    I  5

1, 1, 1     I 2*2*2*5 = 40

$\frac{40/5*4}{40} + \frac{40/2*1}{40} - \frac{40/8*5}{40}$ =

$\frac{8*4}{40} + \frac{20*1}{40} - \frac{5*5}{40}$ =

$\frac{32}{40} + \frac{20}{40} - \frac{25}{40} = \frac{27}{40}$

D)$\frac{7}{15} + \frac{3}{15} - \frac{1}{10}$= $\frac{17}{30}$

MMC de 15, 15 e 10

15, 15, 10  I  2

15, 15, 5  I   5

3, 3, 1      I  3

1, 1, 1        I 2*3*5 = 30

$\frac{30/15*7}{30} + \frac{30/15*3}{30} - \frac{30/10*1}{30}$ =

$\frac{2*7}{30} + \frac{2*3}{30} - \frac{3*1}{30}$ =

$\frac{14}{30} + \frac{6}{30} - \frac{3}{30}$ = $\frac{17}{30}$

uff essa daqui foi dura de responder demorou pra caramba