calcule e muito importante
a) √2×√18
b)√5×√10×√2
c) √3/5 ×√5/3
d) ( ♦√9)☻
e) √6/√3
f) ♥√24/♥√3
g) √3×√12
h)√3/2÷√1/2
Soluções para a tarefa
Respondido por
1
a) √36=6
b) √100=10
c) √1=1
d) √9=3
e) √2
f) √8=2√2
g) √36=6
h) √3
b) √100=10
c) √1=1
d) √9=3
e) √2
f) √8=2√2
g) √36=6
h) √3
JanePots:
se tiver alguma conta errada, pode dizer, é que eu não entendi muito bem os sinais e talvez possa ter feito a conta errada.
Respondido por
1
Olá, Yasmimarques.
![a) \sqrt{2} * \sqrt{18} = \sqrt{2*18} = \sqrt{36} = 6 \\ b) \sqrt{5} * \sqrt{10} * \sqrt{2} = \sqrt{5*10*2} = \sqrt{100} = 10 \\ c) \sqrt{ \frac{3}{5} } * \sqrt{ \frac{5}{3} } = \sqrt{ \frac{3}{5} * \frac{5}{3} } = \sqrt{ \frac{15}{15}} = \sqrt{1} = 1 \\ d) ( \sqrt{9} ) = \sqrt{9} = 3 \\ e) \sqrt{6} / \sqrt{3} = \sqrt{2} \\ f) \sqrt{24} / \sqrt{3} = \sqrt{8} \\ g) \sqrt{3} * \sqrt{12} = \sqrt{3*12}= \sqrt{36} = 6 a) \sqrt{2} * \sqrt{18} = \sqrt{2*18} = \sqrt{36} = 6 \\ b) \sqrt{5} * \sqrt{10} * \sqrt{2} = \sqrt{5*10*2} = \sqrt{100} = 10 \\ c) \sqrt{ \frac{3}{5} } * \sqrt{ \frac{5}{3} } = \sqrt{ \frac{3}{5} * \frac{5}{3} } = \sqrt{ \frac{15}{15}} = \sqrt{1} = 1 \\ d) ( \sqrt{9} ) = \sqrt{9} = 3 \\ e) \sqrt{6} / \sqrt{3} = \sqrt{2} \\ f) \sqrt{24} / \sqrt{3} = \sqrt{8} \\ g) \sqrt{3} * \sqrt{12} = \sqrt{3*12}= \sqrt{36} = 6](https://tex.z-dn.net/?f=a%29++%5Csqrt%7B2%7D+%2A+%5Csqrt%7B18%7D+%3D++%5Csqrt%7B2%2A18%7D+%3D+++%5Csqrt%7B36%7D+%3D+6+%5C%5C+b%29++%5Csqrt%7B5%7D+%2A+%5Csqrt%7B10%7D+%2A+%5Csqrt%7B2%7D+%3D++%5Csqrt%7B5%2A10%2A2%7D+%3D+++%5Csqrt%7B100%7D+%3D+10+%5C%5C+c%29++%5Csqrt%7B+%5Cfrac%7B3%7D%7B5%7D+%7D+%2A+%5Csqrt%7B+%5Cfrac%7B5%7D%7B3%7D+%7D+%3D++%5Csqrt%7B+%5Cfrac%7B3%7D%7B5%7D+%2A+%5Cfrac%7B5%7D%7B3%7D+%7D+%3D+++%5Csqrt%7B+%5Cfrac%7B15%7D%7B15%7D%7D+%3D++%5Csqrt%7B1%7D+%3D+1+%5C%5C+d%29+%28+%5Csqrt%7B9%7D+%29+%3D++%5Csqrt%7B9%7D+%3D+3+%5C%5C+e%29+%5Csqrt%7B6%7D+%2F+%5Csqrt%7B3%7D+%3D++%5Csqrt%7B2%7D++%5C%5C+f%29+%5Csqrt%7B24%7D+%2F+%5Csqrt%7B3%7D++%3D++%5Csqrt%7B8%7D+%5C%5C+g%29+%5Csqrt%7B3%7D+%2A+%5Csqrt%7B12%7D+%3D++%5Csqrt%7B3%2A12%7D%3D++%5Csqrt%7B36%7D+%3D+6)
![h) \sqrt{ \frac{3}{2}} / \sqrt{ \frac{1}{2} } = \sqrt{ \frac{3/1}{2/2}} = \sqrt{\frac{3}{1}} = \sqrt{3} h) \sqrt{ \frac{3}{2}} / \sqrt{ \frac{1}{2} } = \sqrt{ \frac{3/1}{2/2}} = \sqrt{\frac{3}{1}} = \sqrt{3}](https://tex.z-dn.net/?f=+h%29++%5Csqrt%7B+%5Cfrac%7B3%7D%7B2%7D%7D+%2F+%5Csqrt%7B+%5Cfrac%7B1%7D%7B2%7D+%7D+%3D++%5Csqrt%7B+%5Cfrac%7B3%2F1%7D%7B2%2F2%7D%7D+%3D+++%5Csqrt%7B%5Cfrac%7B3%7D%7B1%7D%7D+%3D+%5Csqrt%7B3%7D)
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