Question

Calcule delta da equacao
25t² -121=0

Answer 1

✅ Despois de calcular o delta, concluímos que seu valor é:

        $\Large\displaystyle\text{ \begin{gathered}\boxed{\boxed{\:\:\:\bf \Delta = 12100\:\:\:}}\end{gathered} }$

Dada a equação do segundo grau:

       $\Large\displaystyle\begin{gathered}25t^{2} - 121 = 0 \end{gathered}$

Cujos coeficientes são:

                $\Large\begin{cases}a = 25\\b = 0\\c = -121 \end{cases}$

Calculando o valor de delta, temos:

      $\Large\displaystyle\begin{gathered}\Delta = b^{2} - 4\cdot a\cdot c \end{gathered}$

            $\Large\displaystyle\begin{gathered}= 0^{2} - 4\cdot25\cdot(-121) \end{gathered}$

            $\Large\displaystyle\begin{gathered}= 12100 \end{gathered}$

✅ Portanto, o valor do delta é:

       $\Large\displaystyle\begin{gathered}\Delta = 12100 \end{gathered}$

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