Question

CALCULE: d) (√2+i)-(√3+i) e)(2+4i)(1+3i) f) (1/3+i)(1/2-2i) g)(1+i)(2-i)(3+2i) h)(√2+√3i)(1-√2i)

Answer 1

Boa tarde Nanda

d) 

(√2+i)-(√3+i) = √2 - √3

e)

(2+4i)(1+3i) = 2 + 6i + 4i + 12i² = -10 + 10i 

f)

(1/3+i)(1/2-2i)  = 1/6 - 2i/3 + i/2 - 2i² = 13/6 - i/6 

g) 

(1+i)(2-i)(3+2i) = (2 + 1 + i)*(3 + 2i) = (3 + i)*(3 + 2i) = 7 + 9i 

h)

(√2+√3i)(1-√2i) = √2 + √3i - 2i +√6 = √2 + √6 + √3i - 2i