Question

Calcule com Δ = b²-4ac e x = – b ± √Δ

2.a .

3x²-4x+1=0

Answer 1

3x²-4x+1=0
a = 3; b = - 4; c = 1
∆= b^2-4ac
∆ = (-4)^2 - 4.3.1
∆= 16-12
∆=4

x = [- b +/- √∆]/2a
x = [-(-4)+/- √4]/2.3
x' = [4 + 2]/6 = 6/6 = 1
x" = [4 - 2]/6 = 2/6 (:2)/(:2) = 1/3

R.: (1 ; 1/3)